What is the solution for (dy}{dx}=\frac{x+1)/y ?

The solution for (dy}{dx}=\frac{x+1)/y is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}

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(dy}{dx}=\frac{x+1)/y

\frac{d y}{d x} = \frac{x + 1}{y}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x + 1}{y}

Solve separable ODE:

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

30 y^{^{''}} - 19 y^{^{'}} - 5 y = 0

x \to 7 lim (\frac{4}{( x - 7 ) ^{2}})

\int tan (x^{3}) x^{2} d x

\frac{9 x}{e ^{x}}

x \to \infty lim (x + a)

What is the solution for (dy}{dx}=\frac{x+1)/y ?
The solution for (dy}{dx}=\frac{x+1)/y is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}