What is (\partial)/(\partial x)(e^ysin(x)y) ?

The answer to (\partial)/(\partial x)(e^ysin(x)y) is e^yycos(x)

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(\partial)/(\partial x)(e^ysin(x)y)

\frac{\partial}{\partial x} (e^{y} sin (x) y)

e^{y} y cos (x)

Solution steps

\frac{\partial}{\partial x} (e^{y} sin (x) y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{y} y \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= e^{y} y cos (x)

2 x e^{- 4 x}

4 y^{^{''}} - 4 y^{^{'}} + y = 16 e^{(\frac{t}{2})}

\int 1 - \frac{1}{x ^{2}} d x

\int 7 x^{2} e^{6 x} d x

(x^{- 2} + x)^{- 3}

What is (\partial)/(\partial x)(e^ysin(x)y) ?
The answer to (\partial)/(\partial x)(e^ysin(x)y) is e^yycos(x)