What is (\partial)/(\partial t)(2s^2+t^2) ?

The answer to (\partial)/(\partial t)(2s^2+t^2) is 2t

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(\partial)/(\partial t)(2s^2+t^2)

\frac{\partial}{\partial t} (2 s^{2} + t^{2})

2 t

Solution steps

\frac{\partial}{\partial t} (2 s^{2} + t^{2})

Treat

s

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (2 s^{2}) + \frac{\partial}{\partial t} (t^{2})

\frac{\partial}{\partial t} (2 s^{2}) = 0

\frac{\partial}{\partial t} (t^{2}) = 2 t

= 0 + 2 t

Simplify

= 2 t

x \to 0 lim (1 + \frac{1}{x})

\int x e^{x^{3}} d x

\int 2 x - cos (6 x) d x

(y e^{- 2 x} + y^{3}) d x - e^{- 2 x} d y = 0

What is (\partial)/(\partial t)(2s^2+t^2) ?
The answer to (\partial)/(\partial t)(2s^2+t^2) is 2t