What is the derivative of x+1/(x+1) ?

The derivative of x+1/(x+1) is 1-1/((x+1)^2)

What is the first derivative of x+1/(x+1) ?

The first derivative of x+1/(x+1) is 1-1/((x+1)^2)

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\frac{d}{d x} (x + \frac{1}{x + 1})

1 - \frac{1}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{1}{x + 1})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{1}{x + 1})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x + 1}) = - \frac{1}{( x + 1 ) ^{2}}

= 1 - \frac{1}{( x + 1 ) ^{2}}

f (x) = \frac{1}{x}, at x = 1

\int e^{- t} cos (t) d t

\frac{d}{d t} (\frac{1}{2} e^{- 4 t} cos (8 t))

\int_{0}^{1} π (x^{4} - x) d x

\frac{\partial}{\partial x} (e^{e^{y} x + y})

What is the derivative of x+1/(x+1) ?
The derivative of x+1/(x+1) is 1-1/((x+1)^2)
What is the first derivative of x+1/(x+1) ?
The first derivative of x+1/(x+1) is 1-1/((x+1)^2)