What is (\partial ^2)/(\partial x^2)(x^2-y^2) ?

The answer to (\partial ^2)/(\partial x^2)(x^2-y^2) is 2

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(\partial ^2)/(\partial x^2)(x^2-y^2)

\frac{\partial ^{2}}{\partial x ^{2}} (x^{2} - y^{2})

2

Solution steps

\frac{\partial ^{2}}{\partial x ^{2}} (x^{2} - y^{2})

\frac{\partial}{\partial x} (x^{2} - y^{2}) = 2 x

= \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= 2

\frac{\partial}{\partial x} ((4 - x^{2} - y^{2})^{\frac{1}{2}})

\frac{d}{d t} (\frac{1}{t ^{2} - 2})

\frac{\partial}{\partial x} (ln (4 + 3 x^{2} + 2 y^{2}))

f (x) = 2 sin^{4} (x)

y^{^{''}} - 6 y^{^{'}} = - 2 x - 5

What is (\partial ^2)/(\partial x^2)(x^2-y^2) ?
The answer to (\partial ^2)/(\partial x^2)(x^2-y^2) is 2