What is the integral of (5x^4-4/(x^4)) ?

The integral of (5x^4-4/(x^4)) is x^5+4/(3x^3)+C

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integral of (5x^4-4/(x^4))

\int (5 x^{4} - \frac{4}{x ^{4}}) d x

x^{5} + \frac{4}{3 x ^{3}} + C

Solution steps

\int 5 x^{4} - \frac{4}{x ^{4}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x - \int \frac{4}{x ^{4}} d x

\int 5 x^{4} d x = x^{5}

\int \frac{4}{x ^{4}} d x = - \frac{4}{3 x ^{3}}

= x^{5} - (- \frac{4}{3 x ^{3}})

Simplify

= x^{5} + \frac{4}{3 x ^{3}}

Add a constant to the solution

= x^{5} + \frac{4}{3 x ^{3}} + C

y = (1 - x) (x^{2} - 3)^{2}, (2, - 1)

\frac{1}{1 - x}, 19

\int x^{2} lo g_{3} (x) d x

\int x^{2} + e^{x} d x

y = \frac{x}{8 x - 4}, at x = 2

What is the integral of (5x^4-4/(x^4)) ?
The integral of (5x^4-4/(x^4)) is x^5+4/(3x^3)+C