What is the solution for y^{''}+y=3sin(x) ?

The solution for y^{''}+y=3sin(x) is y=c_{1}cos(x)+c_{2}sin(x)-(3xcos(x))/2

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y^{''}+y=3sin(x)

y^{^{''}} + y = 3 sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{2}

Solution steps

y^{''} (x) + y = 3 sin (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{2}

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{2}

y^{^{''}} + y^{^{'}} = 6 sin (2 x)

x \to 8 lim (\frac{5 x - 2}{x + 8})

\int_{- 2}^{2} x^{2} 4 - x^{2} d x

5 x + 3 x

s \to 1 lim (\frac{s ^{3} - 1}{s - 1})

What is the solution for y^{''}+y=3sin(x) ?
The solution for y^{''}+y=3sin(x) is y=c_{1}cos(x)+c_{2}sin(x)-(3xcos(x))/2