What is the sum from n=1 to infinity of 1/(n^2+n^3) ?

The sum from n=1 to infinity of 1/(n^2+n^3) is converges

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sum from n=1 to infinity of 1/(n^2+n^3)

n = 1 \sum \infty \frac{1}{n ^{2} + n ^{3}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{2} + n ^{3}}

Apply Series Comparison Test:

converges

= converges

x \to 9 lim (7 x - 8)

\frac{\partial}{\partial x} (- 2 ∣ x ∣)

y^{^{''}} - 3 y^{^{'}} + 2 y = x^{2}

\int_{- 1}^{1} (e^{y} - y^{2} + 2) d y

\int \frac{- 6 x ^{2}}{4 x - x ^{2}} d x

What is the sum from n=1 to infinity of 1/(n^2+n^3) ?
The sum from n=1 to infinity of 1/(n^2+n^3) is converges