What is the integral of csc^3(5x) ?

The integral of csc^3(5x) is 1/40 (-cot^2((5x)/2)+4ln|tan((5x)/2)|+tan^2((5x)/2))+C

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integral of csc^3(5x)

\int csc^{3} (5 x) d x

\frac{1}{40} (- cot^{2} (\frac{5 x}{2}) + 4 ln tan (\frac{5 x}{2}) + tan^{2} (\frac{5 x}{2})) + C

Solution steps

\int csc^{3} (5 x) d x

Apply u-substitution

: \int csc^{3} (u) \frac{1}{5} d u

= \int csc^{3} (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int csc^{3} (u) d u

Apply u-substitution

: \int \frac{( 1 + v ^{2} ) ^{2}}{4 v ^{3}} d v

= \frac{1}{5} \cdot \int \frac{( 1 + v ^{2} ) ^{2}}{4 v ^{3}} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \frac{1}{4} \cdot \int \frac{( 1 + v ^{2} ) ^{2}}{v ^{3}} d v

Expand

\frac{( 1 + v ^{2} ) ^{2}}{v ^{3}} : \frac{1}{v ^{3}} + \frac{2}{v} + v

= \frac{1}{5} \cdot \frac{1}{4} \cdot \int \frac{1}{v ^{3}} + \frac{2}{v} + v d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{5} \cdot \frac{1}{4} (\int \frac{1}{v ^{3}} d v + \int \frac{2}{v} d v + \int v d v)

\int \frac{1}{v ^{3}} d v = - \frac{1}{2 v ^{2}}

\int \frac{2}{v} d v = 2 ln ∣ v ∣

\int v d v = \frac{v ^{2}}{2}

= \frac{1}{5} \cdot \frac{1}{4} (- \frac{1}{2 v ^{2}} + 2 ln ∣ v ∣ + \frac{v ^{2}}{2})

Substitute back

= \frac{1}{5} \cdot \frac{1}{4} (- \frac{1}{2 tan ^{2} ( \frac{5 x}{2} )} + 2 ln tan (\frac{5 x}{2}) + \frac{tan ^{2} ( \frac{5 x}{2} )}{2})

Simplify

\frac{1}{5} \cdot \frac{1}{4} (- \frac{1}{2 tan ^{2} ( \frac{5 x}{2} )} + 2 ln tan (\frac{5 x}{2}) + \frac{tan ^{2} ( \frac{5 x}{2} )}{2}) : \frac{1}{40} (- cot^{2} (\frac{5 x}{2}) + 4 ln tan (\frac{5 x}{2}) + tan^{2} (\frac{5 x}{2}))

= \frac{1}{40} (- cot^{2} (\frac{5 x}{2}) + 4 ln tan (\frac{5 x}{2}) + tan^{2} (\frac{5 x}{2}))

Add a constant to the solution

= \frac{1}{40} (- cot^{2} (\frac{5 x}{2}) + 4 ln tan (\frac{5 x}{2}) + tan^{2} (\frac{5 x}{2})) + C

x \to 0 lim (\frac{x ^{2} + 2 ∣ x ∣}{x})

\int \frac{- 4}{( x ^{2} + 16 )} d x

\int \frac{1}{( x ^{2} - 2 x + 5 ) ^{2}} d x

\int \frac{4 x - 3}{x + 1} d x

f (x) = - x^{4} + 18 x^{2} - 11

What is the integral of csc^3(5x) ?
The integral of csc^3(5x) is 1/40 (-cot^2((5x)/2)+4ln|tan((5x)/2)|+tan^2((5x)/2))+C