What is the integral of ((12)/(\sqrt[3]{10x+4)}-3) ?

The integral of ((12)/(\sqrt[3]{10x+4)}-3) is 9/5 (10x+4)^{2/3}-3x+C

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integral of ((12)/(\sqrt[3]{10x+4)}-3)

\frac{9}{5} (10 x + 4)^{\frac{2}{3}} - 3 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 3 d x = 3 x

= \frac{9}{5} (10 x + 4)^{\frac{2}{3}} - 3 x

Add a constant to the solution

= \frac{9}{5} (10 x + 4)^{\frac{2}{3}} - 3 x + C

\frac{d}{d x} (9^{x^{2} - x})

\int \frac{cos ( ln ( x ) - 6 )}{x} d x

30 (2 e^{x^{2}} x^{2} + e^{x^{2}})

x \to + 4 lim (9 x + ∣ x - 4 ∣)

- sin^{3} (x)

What is the integral of ((12)/(\sqrt[3]{10x+4)}-3) ?
The integral of ((12)/(\sqrt[3]{10x+4)}-3) is 9/5 (10x+4)^{2/3}-3x+C