What is the derivative of f(x)=-x^2+8x-8 ?

The derivative of f(x)=-x^2+8x-8 is -2x+8

What is the first derivative of f(x)=-x^2+8x-8 ?

The first derivative of f(x)=-x^2+8x-8 is -2x+8

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derivative of

f (x) = - x^{2} + 8 x - 8

- 2 x + 8

Solution steps

\frac{d}{d x} (- x^{2} + 8 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (8) = 0

= - 2 x + 8 - 0

Simplify

= - 2 x + 8

- 3 e^{t}

\frac{x ^{2} - 2}{e ^{2 x}}

x \to - 1 lim (lo g_{10} (x))

\int (8 x^{2} + 3 x^{- 2}) d x

x \to 0 - lim (x^{2} e^{\frac{1}{x}})

What is the derivative of f(x)=-x^2+8x-8 ?
The derivative of f(x)=-x^2+8x-8 is -2x+8
What is the first derivative of f(x)=-x^2+8x-8 ?
The first derivative of f(x)=-x^2+8x-8 is -2x+8