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Popular >

y^'=xe^{y-x^2}

Solution

y^{^{'}} = x e^{y - x^{2}}

Solution

y = - ln (\frac{1}{2} e^{- x^{2}} - c_{1})

Solution steps

y^{'} (x) = x e^{y - x^{2}}

Solve separable ODE:

y = - ln (\frac{1}{2} e^{- x^{2}} - c_{1})

y = - ln (\frac{1}{2} e^{- x^{2}} - c_{1})

Popular Examples

taylor ln(x),1 taylor

ln (x), 1

integral from 0 to sqrt(pi of)xsin(x^2)

\int_{0}^{π} x sin (x^{2}) d x

limit as x approaches-5 of (x^2-5)/(x+5)

x \to - 5 lim (\frac{x ^{2} - 5}{x + 5})

area x=2y^2,x=2 area

x = 2 y^{2}, x = 2

y^{''}-2y^'-15y=e^{(3x)}cos(2x)

y^{^{''}} - 2 y^{^{'}} - 15 y = e^{(3 x)} cos (2 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=xe^{y-x^2} ?
The solution for y^'=xe^{y-x^2} is y=-ln(1/2 e^{-x^2}-c_{1})