What is the derivative of 564+x(36x^{0.6}-107) ?

The derivative of 564+x(36x^{0.6}-107) is 57.6x^{0.6}-107

What is the first derivative of 564+x(36x^{0.6}-107) ?

The first derivative of 564+x(36x^{0.6}-107) is 57.6x^{0.6}-107

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\frac{d}{d x} (564 + x (36 x^{0.6} - 107))

57.6 x^{0.6} - 107

Solution steps

\frac{d}{d x} (564 + x (36 x^{0.6} - 107))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (564) + \frac{d}{d x} (x (36 x^{0.6} - 107))

\frac{d}{d x} (564) = 0

\frac{d}{d x} (x (36 x^{0.6} - 107)) = 57.6 x^{0.6} - 107

= 0 + 57.6 x^{0.6} - 107

Simplify

= 57.6 x^{0.6} - 107

x \to - 1 - lim (\frac{x}{( x + 1 ) ^{3}})

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What is the derivative of 564+x(36x^{0.6}-107) ?
The derivative of 564+x(36x^{0.6}-107) is 57.6x^{0.6}-107
What is the first derivative of 564+x(36x^{0.6}-107) ?
The first derivative of 564+x(36x^{0.6}-107) is 57.6x^{0.6}-107