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Popular >

area x=2y,y^2=4x

Solution

area

x = 2 y, y^{2} = 4 x

Solution

\frac{64}{3}

+1

Decimal Notation

21.33333 \dots

Solution steps

Isolate

y

for

x = 2 y : y = \frac{x}{2}

Isolate

y

for

y^{2} = 4 x : y = 2 x, y = - 2 x

f_{1} (x) = \frac{x}{2}

f_{2} (x) = 2 x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{2} = 2 x : x = 16, x = 0

\frac{x}{2} = - 2 x : x = 0

2 x = - 2 x : x = 0

= \int_{0}^{16} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \int_{0}^{16} \frac{x}{2} - 2 x d x

\int_{0}^{16} \frac{x}{2} - 2 x d x = \frac{64}{3}

= \frac{64}{3}

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\frac{450}{s ( s + 3 ) ^{2}}

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Frequently Asked Questions (FAQ)

What is area x=2y,y^2=4x ?
The answer to area x=2y,y^2=4x is 64/3