What is the solution for y^'=(7x^6e^{y/x}+x^4y^2)/(x^5y) ?

The solution for y^'=(7x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((7ln(x)+c_{1})/e)x-x

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y^'=(7x^6e^{y/x}+x^4y^2)/(x^5y)

y^{^{'}} = \frac{7 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

y = - W (\frac{7 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{7 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

Solve using substitution:

y = - W (\frac{7 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{7 ln ( x ) + c _{1}}{e}) x - x

(- 8, - 3), (- 3, 4)

f (x) = \frac{5}{x}, at x = 1

\frac{1}{2 s + 3}

\frac{\partial}{\partial y} (x y e^{2 y})

x \to 1 lim (arcsec (x))

What is the solution for y^'=(7x^6e^{y/x}+x^4y^2)/(x^5y) ?
The solution for y^'=(7x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((7ln(x)+c_{1})/e)x-x