What is the solution for y^{''}+9y^'=0,y(0)=1,y^'(0)=1 ?

The solution for y^{''}+9y^'=0,y(0)=1,y^'(0)=1 is y=1+1/9-1/9 e^{-9t}

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y^{''}+9y^'=0,y(0)=1,y^'(0)=1

y^{^{''}} + 9 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

y = 1 + \frac{1}{9} - \frac{1}{9} e^{- 9 t}

Solution steps

y^{''} (t) + 9 y^{'} (t) = 0

Solve linear ODE:

y = 1 + \frac{1}{9} - \frac{1}{9} e^{- 9 t}

y = 1 + \frac{1}{9} - \frac{1}{9} e^{- 9 t}

\int \frac{y ^{2} - 9}{y} d y

9 x - x^{2}, 2 x, 0, 7

\frac{d}{d x} (4 - 4 x^{2})

\frac{d ^{2} y}{d x ^{2}} + (\frac{d y}{d x})^{2} = 0

h (x) = x^{\frac{6}{5}}

What is the solution for y^{''}+9y^'=0,y(0)=1,y^'(0)=1 ?
The solution for y^{''}+9y^'=0,y(0)=1,y^'(0)=1 is y=1+1/9-1/9 e^{-9t}