What is the solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=5 ?

The solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=5 is y= 4/((x^2+1)^4)+1

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(x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=5

(x^{2} + 1) (\frac{d y}{d x}) + 8 x (y - 1) = 0, y (0) = 5

y = \frac{4}{( x ^{2} + 1 ) ^{4}} + 1

Solution steps

(x^{2} + 1) (\frac{d y}{d x}) + 8 x (y - 1) = 0

Solve separable ODE:

y = \frac{4}{( x ^{2} + 1 ) ^{4}} + 1

y = \frac{4}{( x ^{2} + 1 ) ^{4}} + 1

\int 3 x^{5} e^{x} d x

6 x + \frac{d y}{d x} = 0

\frac{\partial}{\partial x} (x (x^{2} + y^{2} + z^{2})^{m})

\frac{d}{d x} (\frac{1}{f ( x )})

\int_{1}^{- 1} (x - 1) (3 x + 2) d x

What is the solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=5 ?
The solution for (x^2+1)((dy)/(dx))+8x(y-1)=0,y(0)=5 is y= 4/((x^2+1)^4)+1