What is area y^2=4x,y^2=8x-4,x ?

The answer to area y^2=4x,y^2=8x-4,x is No Solution

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area y^2=4x,y^2=8x-4,x

area

y^{2} = 4 x, y^{2} = 8 x - 4, x

No Solution

Solution steps

Isolate

y

for

y^{2} = 4 x : y = 2 x, y = - 2 x

Isolate

y

for

y^{2} = 8 x - 4 : y = 2 2 x - 1, y = - 2 2 x - 1

f_{1} (x) = 2 x

f_{2} (x) = - 2 x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

2 x = - 2 x : x = 0

2 x = 2 2 x - 1 : x = 1

2 x = - 2 2 x - 1 :

No Solution for

x \in R

2 x = x : x = 4, x = 0

- 2 x = 2 2 x - 1 :

No Solution for

x \in R

- 2 x = - 2 2 x - 1 : x = 1

- 2 x = x : x = 0

2 2 x - 1 = - 2 2 x - 1 : x = \frac{1}{2}

2 2 x - 1 = x : x = 2 (2 + 3), x = 2 (2 - 3)

- 2 2 x - 1 = x :

No Solution for

x \in R

Curves not bounded

= No Solution

x \to 42 lim (\frac{x ^{2}}{6} - \frac{7}{x})

\frac{1 + 10 s}{s ^{2} + 10.1 s + 1}

\frac{\partial}{\partial x} ((x y - 5)^{2})

x \to 0 lim (\frac{( e ) ^{x}}{x})

What is area y^2=4x,y^2=8x-4,x ?
The answer to area y^2=4x,y^2=8x-4,x is No Solution