What is the sum from n=1 to infinity of 2/(pi^n) ?

The sum from n=1 to infinity of 2/(pi^n) is converges

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sum from n=1 to infinity of 2/(pi^n)

n = 1 \sum \infty \frac{2}{π ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{2}{π ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{1}{π ^{n}}

Apply Series Ratio Test:

converges

= 2 converges

= converges

\int \frac{x ^{5}}{5} d x

x \to \infty lim (\frac{4 ^{x}}{3 ^{x - 1}})

\frac{\partial}{\partial x} (\frac{y}{y ^{2} + x ^{2}})

\frac{d}{d x} (\frac{2 x ^{3} - x ^{2} + 5 x}{x ^{2} - 25})

What is the sum from n=1 to infinity of 2/(pi^n) ?
The sum from n=1 to infinity of 2/(pi^n) is converges