What is the solution for y^'= y/(50+t)5,y(0)=30 ?

The solution for y^'= y/(50+t)5,y(0)=30 is y=(3(50+t)^5)/(31250000)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'= y/(50+t)5,y(0)=30

y^{^{'}} = \frac{y}{50 + t} 5, y (0) = 30

y = \frac{3 ( 50 + t ) ^{5}}{31250000}

Solution steps

y^{'} (t) = \frac{y}{50 + t} 5

Solve separable ODE:

y = \frac{3 ( 50 + t ) ^{5}}{31250000}

y = \frac{3 ( 50 + t ) ^{5}}{31250000}

\int 16 x^{3} e^{x^{4} + 1} d x

\int \frac{ln ( 2 x )}{x ^{2}} d x

y^{\frac{1}{2}} (\frac{d y}{d x}) + y^{\frac{3}{2}} = 1, y (0) = 9

x \to 0 lim (e^{- \frac{2}{x ^{3}}})

f (x) = (x^{3} + 7) e^{x}

What is the solution for y^'= y/(50+t)5,y(0)=30 ?
The solution for y^'= y/(50+t)5,y(0)=30 is y=(3(50+t)^5)/(31250000)