What is the sum from n=1 to infinity}\sqrt{5 of*2/n ?

The sum from n=1 to infinity}\sqrt{5 of*2/n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity}\sqrt{5 of*2/n

n = 1 \sum \infty 5 \cdot \frac{2}{n}

diverges

Solution steps

n = 1 \sum \infty 5 \frac{2}{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot 2 \cdot n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= 5 \cdot 2 diverges

= diverges

x \to 6 lim (\frac{x ^{2} - 9 x + 18}{x - 6})

y = 6 x, y = \frac{3}{2} x, y = 7 - x^{2}

\frac{d}{d x} (2^{3^{4^{x}}})

\int e^{2 x^{2}} x d x

\int \frac{k x}{1 - x} d x

What is the sum from n=1 to infinity}\sqrt{5 of*2/n ?
The sum from n=1 to infinity}\sqrt{5 of*2/n is diverges