What is the limit as x approaches 3 of (x-3)/(x^2-9) ?

The limit as x approaches 3 of (x-3)/(x^2-9) is 1/6

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limit as x approaches 3 of (x-3)/(x^2-9)

x \to 3 lim (\frac{x - 3}{x ^{2} - 9})

\frac{1}{6}

Decimal Notation

0.16666 \dots

Solution steps

x \to 3 lim (\frac{x - 3}{x ^{2} - 9})

Simplify

\frac{x - 3}{x ^{2} - 9} : \frac{1}{x + 3}

= x \to 3 lim (\frac{1}{x + 3})

Plug in the value

x = 3

= \frac{1}{3 + 3}

Simplify

= \frac{1}{6}

f (x) = (\frac{x + 7}{x + 9})^{6}

\int \frac{1}{4 x 16 x ^{2} - 25} d x

- 3 e^{- 3 x} + e^{4 x} \cdot 4

\int y^{2} e^{3 y} d y

n = 0 \sum \infty \frac{1}{n + 7}

What is the limit as x approaches 3 of (x-3)/(x^2-9) ?
The limit as x approaches 3 of (x-3)/(x^2-9) is 1/6