What is the derivative of-2cos(x-x) ?

The derivative of-2cos(x-x) is 2sin(x)-1

What is the first derivative of-2cos(x-x) ?

The first derivative of-2cos(x-x) is 2sin(x)-1

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\frac{d}{d x} (- 2 cos (x) - x)

2 sin (x) - 1

Solution steps

\frac{d}{d x} (- 2 cos (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 cos (x)) - \frac{d x}{d x}

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d x}{d x} = 1

= - (- 2 sin (x)) - 1

Simplify

= 2 sin (x) - 1

\int sin (a - x) d x

x \to 2 lim (\frac{( x + 3 )}{x + 4})

\frac{d}{d t} (t sin (π t))

\int \frac{1}{t ^{2}} cos (\frac{1}{t} - 1) d t

y = \frac{4}{x ^{5}}

What is the derivative of-2cos(x-x) ?
The derivative of-2cos(x-x) is 2sin(x)-1
What is the first derivative of-2cos(x-x) ?
The first derivative of-2cos(x-x) is 2sin(x)-1