What is the tangent of f(x)=sqrt(7x+11),\at x=2 ?

The tangent of f(x)=sqrt(7x+11),\at x=2 is y= 7/10 x+18/5

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tangent of f(x)=sqrt(7x+11),\at x=2

tangent of

f (x) = 7 x + 11, at x = 2

y = \frac{7}{10} x + \frac{18}{5}

Solution steps

Find the tangent point:

(2, 5)

Find the slope of

f (x) = 7 x + 11 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 11}

Compute the slope of

f (x) = 7 x + 11

x = 2 : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(2, 5) : y = \frac{7}{10} x + \frac{18}{5}

y = \frac{7}{10} x + \frac{18}{5}

\frac{d y}{d x} = \frac{cos ( 8 x )}{e ^{8 y}}

g (x) = (5 - x)^{2} (2 x - 1)^{5}

\int_{- 8}^{10} \frac{x}{2} + 10 d x

\int \frac{y ^{2}}{4} d y

t (sin (9 t) + e^{- 2 t})

What is the tangent of f(x)=sqrt(7x+11),\at x=2 ?
The tangent of f(x)=sqrt(7x+11),\at x=2 is y= 7/10 x+18/5