What is the tangent of f(x)=x^2-5x+5,(0,5) ?

The tangent of f(x)=x^2-5x+5,(0,5) is y=-5x+5

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tangent of f(x)=x^2-5x+5,(0,5)

tangent of

f (x) = x^{2} - 5 x + 5, (0, 5)

y = - 5 x + 5

Solution steps

Find the slope of

f (x) = x^{2} - 5 x + 5 : \frac{df ( x )}{d x} = 2 x - 5

Compute the slope of

f (x) = x^{2} - 5 x + 5

(0, 5) : m = - 5

Find the line with slope m=

- 5

and passing through

(0, 5) : y = - 5 x + 5

y = - 5 x + 5

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What is the tangent of f(x)=x^2-5x+5,(0,5) ?
The tangent of f(x)=x^2-5x+5,(0,5) is y=-5x+5