What is the solution for f^'(x)=3arctan(x^2-3x+2) ?

The solution for f^'(x)=3arctan(x^2-3x+2) is f(x)=integral of 3arctan(x^2-3x+2)

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f^'(x)=3arctan(x^2-3x+2)

f^{^{'}} (x) = 3 arctan (x^{2} - 3 x + 2)

f (x) = \int 3 arctan (x^{2} - 3 x + 2) d x

Solution steps

f^{'} (x) = 3 arctan (x^{2} - 3 x + 2)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 3 arctan (x^{2} - 3 x + 2) d x

f (x) = \int 3 arctan (x^{2} - 3 x + 2) d x

\int 1 - 4 w^{2} d w

\int \frac{sin ( 2 x )}{cos ^{3} ( 2 x )} d x

x, \frac{1}{x ^{2}}, 1, 3

\frac{d y}{d x} = - 5 y x, y (0) = 50

x 2^{x}

What is the solution for f^'(x)=3arctan(x^2-3x+2) ?
The solution for f^'(x)=3arctan(x^2-3x+2) is f(x)=integral of 3arctan(x^2-3x+2)