What is the first derivative of xy^2 ?

The first derivative of xy^2 is y^2

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derivative of xy^2

derivative of

x y^{2}

y^{2}

Solution steps

\frac{d}{d x} (x y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= y^{2} \cdot 1

Simplify

= y^{2}

x \to 2 lim (\frac{sin ( 4 x - 8 )}{3 x - 6})

\frac{d}{d x} (\frac{( e ^{x} )}{x})

f (x) = e^{x 7 x + 6}

\frac{7}{2 s ^{2 + 8}}

\int cos^{2 - 2} (x) d x