What is (\partial)/(\partial x)(4-x^2-y^2) ?

The answer to (\partial)/(\partial x)(4-x^2-y^2) is -2x

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(\partial)/(\partial x)(4-x^2-y^2)

\frac{\partial}{\partial x} (4 - x^{2} - y^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (4 - x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (4) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 2 x - 0

Simplify

= - 2 x

121 y^{^{''}} - 154 y^{^{'}} + 85 y = 0

- \frac{4}{3} x^{\frac{2}{3}}

\frac{\partial}{\partial x} (e^{- x} cos (yz) z)

\frac{d}{d x} (\frac{x ^{6}}{12} + \frac{1}{8 x ^{4}})

(3, - 9), (52, 1)

What is (\partial)/(\partial x)(4-x^2-y^2) ?
The answer to (\partial)/(\partial x)(4-x^2-y^2) is -2x