What is the derivative of (2x+7^3) ?

The derivative of (2x+7^3) is 6(2x+7)^2

What is the first derivative of (2x+7^3) ?

The first derivative of (2x+7^3) is 6(2x+7)^2

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\frac{d}{d x} ((2 x + 7)^{3})

6 (2 x + 7)^{2}

Solution steps

\frac{d}{d x} ((2 x + 7)^{3})

Apply the chain rule:

3 (2 x + 7)^{2} \frac{d}{d x} (2 x + 7)

= 3 (2 x + 7)^{2} \frac{d}{d x} (2 x + 7)

\frac{d}{d x} (2 x + 7) = 2

= 3 (2 x + 7)^{2} \cdot 2

Simplify

= 6 (2 x + 7)^{2}

\frac{4}{s} (\frac{1}{6 + 5 s})

\int_{0}^{\frac{π}{2}} - 8 cos^{5} (x) d x

\frac{\partial}{\partial x} (3 x^{2} (5 x + 7 y))

\int 5 tan (x) sec^{4} (x) d x

tan (x) \frac{d y}{d x} = y

What is the derivative of (2x+7^3) ?
The derivative of (2x+7^3) is 6(2x+7)^2
What is the first derivative of (2x+7^3) ?
The first derivative of (2x+7^3) is 6(2x+7)^2