What is the integral of-1/(sqrt(x)) ?

The integral of-1/(sqrt(x)) is -2sqrt(x)+C

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integral of-1/(sqrt(x))

\int - \frac{1}{x} d x

- 2 x + C

Solution steps

\int - \frac{1}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= - 2 x^{\frac{1}{2}}

Apply radical rule:

= - 2 x

Add a constant to the solution

= - 2 x + C

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\int_{0}^{5} x^{3} x^{2} + 25 d x

What is the integral of-1/(sqrt(x)) ?
The integral of-1/(sqrt(x)) is -2sqrt(x)+C