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Popular >

integral of x^2+4x-8

Solution

\int x^{2} + 4 x - 8 d x

Solution

\frac{x ^{3}}{3} + 2 x^{2} - 8 x + C

Solution steps

\int x^{2} + 4 x - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 4 x d x - \int 8 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 8 d x = 8 x

= \frac{x ^{3}}{3} + 2 x^{2} - 8 x

Add a constant to the solution

= \frac{x ^{3}}{3} + 2 x^{2} - 8 x + C

Popular Examples

integral from-1 to-2 of ((16-x^3)/(x^3))

\int_{- 1}^{- 2} (\frac{16 - x ^{3}}{x ^{3}}) d x

f (x) = x - 7

derivative of (sqrt(x)+x^3/(x^2))

\frac{d}{d x} (\frac{x + x ^{3}}{x ^{2}})

derivative of xsqrt(18-x^2)derivative of

x 18 - x^{2}

laplacetransform te^{3t}laplace transform

t e^{3 t}

Frequently Asked Questions (FAQ)

What is the integral of x^2+4x-8 ?
The integral of x^2+4x-8 is (x^3)/3+2x^2-8x+C