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Popular >

y^'+5y=5-e^t

Solution

y^{^{'}} + 5 y = 5 - e^{t}

Solution

y = 1 - \frac{e ^{t}}{6} + \frac{c _{1}}{e ^{5 t}}

Solution steps

y^{'} (t) + 5 y = 5 - e^{t}

Solve linear ODE:

y = 1 - \frac{e ^{t}}{6} + \frac{c _{1}}{e ^{5 t}}

y = 1 - \frac{e ^{t}}{6} + \frac{c _{1}}{e ^{5 t}}

Popular Examples

tangent of 3x^2+6 tangent of

3 x^{2} + 6

integral from 6 to 8 of (16)/((x-6)^3)

\int_{6}^{8} \frac{16}{( x - 6 ) ^{3}} d x

derivative of x(2x+5^{1/3})

\frac{d}{d x} (x (2 x + 5)^{\frac{1}{3}})

tangent of f(x)=2x^3+6x^2-49x+24 tangent of

f (x) = 2 x^{3} + 6 x^{2} - 49 x + 24

(\partial}{\partial x}(zarctan(\frac{3y)/x))

\frac{\partial}{\partial x} (z arctan (\frac{3 y}{x}))

Frequently Asked Questions (FAQ)

What is the solution for y^'+5y=5-e^t ?
The solution for y^'+5y=5-e^t is y=1-(e^t)/6+(c_{1})/(e^{5t)}