What is implicit x-cos(5y)=0 ?

The answer to implicit x-cos(5y)=0 is (dy)/(dx)=-1/(5sin(5y))

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implicit x-cos(5y)=0

implicit derivative

x - cos (5 y) = 0

\frac{d y}{d x} = - \frac{1}{5 sin ( 5 y )}

Solution steps

x - cos (5 y) = 0

Treat

y

y (x)

Differentiate both sides:

1 + 5 sin (5 y) \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{1}{5 sin ( 5 y )}

\frac{d y}{d x} = - \frac{1}{5 sin ( 5 y )}

\int_{0}^{π} 19 sin^{2} (2 x) d x

x \to 0 lim (ln (2 x))

ln (\frac{x ^{2} ( x ^{3} + 1 )}{e ^{2 x}})

\frac{d}{d x} (4 + x - 7)

\frac{x ^{2} - 3 x}{x + 1}

What is implicit x-cos(5y)=0 ?
The answer to implicit x-cos(5y)=0 is (dy)/(dx)=-1/(5sin(5y))