What is the derivative of f(x)=x^3-4x^2-6x+8 ?

The derivative of f(x)=x^3-4x^2-6x+8 is 3x^2-8x-6

What is the first derivative of f(x)=x^3-4x^2-6x+8 ?

The first derivative of f(x)=x^3-4x^2-6x+8 is 3x^2-8x-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{3} - 4 x^{2} - 6 x + 8

3 x^{2} - 8 x - 6

Solution steps

\frac{d}{d x} (x^{3} - 4 x^{2} - 6 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (8) = 0

= 3 x^{2} - 8 x - 6 + 0

Simplify

= 3 x^{2} - 8 x - 6

\int \frac{1}{x} \cdot ln (x) d x

\int w d w

\frac{d}{d x} (6 x^{2} + 4)

What is the derivative of f(x)=x^3-4x^2-6x+8 ?
The derivative of f(x)=x^3-4x^2-6x+8 is 3x^2-8x-6
What is the first derivative of f(x)=x^3-4x^2-6x+8 ?
The first derivative of f(x)=x^3-4x^2-6x+8 is 3x^2-8x-6