What is the derivative of ln(((1-2x))/2) ?

The derivative of ln(((1-2x))/2) is -2/(1-2x)

What is the first derivative of ln(((1-2x))/2) ?

The first derivative of ln(((1-2x))/2) is -2/(1-2x)

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derivative of

ln (\frac{( 1 - 2 x )}{2})

- \frac{2}{1 - 2 x}

Solution steps

\frac{d}{d x} (ln (\frac{1 - 2 x}{2}))

Apply the chain rule:

\frac{1}{\frac{1 - 2 x}{2}} \frac{d}{d x} (\frac{1 - 2 x}{2})

= \frac{1}{\frac{1 - 2 x}{2}} \frac{d}{d x} (\frac{1 - 2 x}{2})

\frac{d}{d x} (\frac{1 - 2 x}{2}) = - 1

= \frac{1}{\frac{1 - 2 x}{2}} (- 1)

Simplify

= - \frac{2}{1 - 2 x}

\frac{d y}{d x} + 3 y = e^{2 x}

n = 1 \sum \infty x^{n - 1}

1 - x^{2}, 0, 2

g (t) = t^{3} (2 t^{2} - t^{- 1})

3 x^{2}, 3 x^{3}

What is the derivative of ln(((1-2x))/2) ?
The derivative of ln(((1-2x))/2) is -2/(1-2x)
What is the first derivative of ln(((1-2x))/2) ?
The first derivative of ln(((1-2x))/2) is -2/(1-2x)