What is the derivative of f(x)=(x-3)(2x+1) ?

The derivative of f(x)=(x-3)(2x+1) is 4x-5

What is the first derivative of f(x)=(x-3)(2x+1) ?

The first derivative of f(x)=(x-3)(2x+1) is 4x-5

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derivative of

f (x) = (x - 3) (2 x + 1)

4 x - 5

Solution steps

\frac{d}{d x} ((x - 3) (2 x + 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 3, g = 2 x + 1

= \frac{d}{d x} (x - 3) (2 x + 1) + \frac{d}{d x} (2 x + 1) (x - 3)

\frac{d}{d x} (x - 3) = 1

\frac{d}{d x} (2 x + 1) = 2

= 1 \cdot (2 x + 1) + 2 (x - 3)

Simplify

1 \cdot (2 x + 1) + 2 (x - 3) : 4 x - 5

= 4 x - 5

\frac{1}{2} \frac{d y}{d x} = y + 2

\frac{\partial}{\partial y} (sin (x) + cos (y))

\frac{d}{d t} (\frac{sin ( t )}{1 - cos ( t )})

d x + \frac{1}{y ^{4}} d y = 0

\int_{1}^{3} 3 x^{2} + 4 x + 3 d x

What is the derivative of f(x)=(x-3)(2x+1) ?
The derivative of f(x)=(x-3)(2x+1) is 4x-5
What is the first derivative of f(x)=(x-3)(2x+1) ?
The first derivative of f(x)=(x-3)(2x+1) is 4x-5