What is (\partial)/(\partial y)(cos(x)sin(y)) ?

The answer to (\partial)/(\partial y)(cos(x)sin(y)) is cos(x)cos(y)

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(\partial)/(\partial y)(cos(x)sin(y))

\frac{\partial}{\partial y} (cos (x) sin (y))

cos (x) cos (y)

Solution steps

\frac{\partial}{\partial y} (cos (x) sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x) \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= cos (x) cos (y)

x \to + 0 lim (\frac{sin ( 40 )}{x})

f (x) = cos (cos (x))

\frac{d ^{4}}{d x ^{4}} (\frac{1}{x})

n = 0 \sum \infty (n + 1) e^{- n}

\frac{d}{d x} (2^{3^{x}})

What is (\partial)/(\partial y)(cos(x)sin(y)) ?
The answer to (\partial)/(\partial y)(cos(x)sin(y)) is cos(x)cos(y)