What is the solution for (dy)/(dx)+1/x y=10x^2 ?

The solution for (dy)/(dx)+1/x y=10x^2 is y=(5x^3)/2+(c_{1})/x

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(dy)/(dx)+1/x y=10x^2

\frac{d y}{d x} + \frac{1}{x} y = 10 x^{2}

y = \frac{5 x ^{3}}{2} + \frac{c _{1}}{x}

Solution steps

\frac{d y}{d x} + \frac{1}{x} y = 10 x^{2}

Solve linear ODE:

y = \frac{5 x ^{3}}{2} + \frac{c _{1}}{x}

y = \frac{5 x ^{3}}{2} + \frac{c _{1}}{x}

\int x 1 - x^{2} - x^{2} d x

\int (x^{2} e^{- x^{3}}) d x

\frac{\partial}{\partial y} (x y z^{2} tan (y t))

y = 2 - 6 x, at x = - 1

\frac{s}{s ^{2} - 3}

What is the solution for (dy)/(dx)+1/x y=10x^2 ?
The solution for (dy)/(dx)+1/x y=10x^2 is y=(5x^3)/2+(c_{1})/x