What is taylor sin(x)2 ?

The answer to taylor sin(x)2 is 2x-1/3 x^3+1/60 x^5-1/2520 x^7+1/181440 x^9+\ldots

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taylor sin(x)2

taylor

sin (x) 2

2 x - \frac{1}{3} x^{3} + \frac{1}{60} x^{5} - \frac{1}{2520} x^{7} + \frac{1}{181440} x^{9} + \dots

Solution steps

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( sin ( x ) \cdot 2 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( sin ( x ) \cdot 2 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( sin ( x ) \cdot 2 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{2}{1 !} x + \frac{0}{2 !} x^{2} + \frac{- 2}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{2}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{- 2}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{2}{9 !} x^{9} + \dots

Refine

= 2 x - \frac{1}{3} x^{3} + \frac{1}{60} x^{5} - \frac{1}{2520} x^{7} + \frac{1}{181440} x^{9} + \dots

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\frac{e ^{x}}{7 x ^{2}}

What is taylor sin(x)2 ?
The answer to taylor sin(x)2 is 2x-1/3 x^3+1/60 x^5-1/2520 x^7+1/181440 x^9+\ldots