What is the derivative of (\sqrt[3]{x})/(x-3) ?

The derivative of (\sqrt[3]{x})/(x-3) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}

What is the first derivative of (\sqrt[3]{x})/(x-3) ?

The first derivative of (\sqrt[3]{x})/(x-3) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}

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derivative of

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x - 3) = 1

Simplify

a^{4} + cos^{4} (x)

\int_{0}^{1} y d y

x \to 0 lim (\frac{- 6}{x ^{2}})

\int \frac{2}{( x + 1 ) ( x + 2 )} d x

n = 1 \sum \infty 2 (0.4)^{n - 1}

What is the derivative of (\sqrt[3]{x})/(x-3) ?
The derivative of (\sqrt[3]{x})/(x-3) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}
What is the first derivative of (\sqrt[3]{x})/(x-3) ?
The first derivative of (\sqrt[3]{x})/(x-3) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}