What is the sum from n=1 to infinity of (5n)/(6n+5) ?

The sum from n=1 to infinity of (5n)/(6n+5) is diverges

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sum from n=1 to infinity of (5n)/(6n+5)

n = 1 \sum \infty \frac{5 n}{6 n + 5}

diverges

Solution steps

n = 1 \sum \infty \frac{5 n}{6 n + 5}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{n}{6 n + 5}

Apply Series Divergence Test:

diverges

= 5 diverges

= diverges

y = arccot (7 t)

\frac{d}{d x} (\frac{x}{x - y})

\frac{d}{d x} (- \frac{81}{x ^{4}})

\int 1 + 6 x^{\frac{1}{2}} d x

f (x) = x \cdot sin (x)

What is the sum from n=1 to infinity of (5n)/(6n+5) ?
The sum from n=1 to infinity of (5n)/(6n+5) is diverges