What is the derivative of-3sin(2x) ?

The derivative of-3sin(2x) is -6cos(2x)

What is the first derivative of-3sin(2x) ?

The first derivative of-3sin(2x) is -6cos(2x)

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\frac{d}{d x} (- 3 sin (2 x))

- 6 cos (2 x)

Solution steps

\frac{d}{d x} (- 3 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 3 cos (2 x) \cdot 2

Simplify

= - 6 cos (2 x)

g (t) = \frac{t - t}{t ^{\frac{1}{3}}}

\int \frac{e ^{x}}{e ^{x} + e ^{- x}} d x

n = 0 \sum \infty \frac{1}{2 ^{2^{n}}}

y = π^{3 x + 1}

\frac{d z}{d z}

What is the derivative of-3sin(2x) ?
The derivative of-3sin(2x) is -6cos(2x)
What is the first derivative of-3sin(2x) ?
The first derivative of-3sin(2x) is -6cos(2x)