What is the derivative of f(x)=cos(a^9+x^9) ?

The derivative of f(x)=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8

What is the first derivative of f(x)=cos(a^9+x^9) ?

The first derivative of f(x)=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8

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derivative of

f (x) = cos (a^{9} + x^{9})

- sin (a^{9} + x^{9}) \cdot 9 x^{8}

Solution steps

\frac{d}{d x} (cos (a^{9} + x^{9}))

Apply the chain rule:

- sin (a^{9} + x^{9}) \frac{d}{d x} (a^{9} + x^{9})

= - sin (a^{9} + x^{9}) \frac{d}{d x} (a^{9} + x^{9})

\frac{d}{d x} (a^{9} + x^{9}) = 9 x^{8}

= - sin (a^{9} + x^{9}) \cdot 9 x^{8}

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What is the derivative of f(x)=cos(a^9+x^9) ?
The derivative of f(x)=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8
What is the first derivative of f(x)=cos(a^9+x^9) ?
The first derivative of f(x)=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8