What is the tangent of 3x^2+2x,\at x=-1 ?

The tangent of 3x^2+2x,\at x=-1 is y=-4x-3

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tangent of 3x^2+2x,\at x=-1

tangent of

3 x^{2} + 2 x, at x = - 1

y = - 4 x - 3

Solution steps

Find the tangent point:

(- 1, 1)

Find the slope of

y = 3 x^{2} + 2 x : \frac{d y}{d x} = 6 x + 2

Compute the slope of

y = 3 x^{2} + 2 x

x = - 1 : m = - 4

Find the line with slope m=

- 4

and passing through

(- 1, 1) : y = - 4 x - 3

y = - 4 x - 3

y = \frac{π x}{12}

\frac{d}{d x} (2 e^{- x} cos (x))

f (x) = \frac{2 x ^{2} + 2 x + 4}{x}

\int e^{x^{2} - 1} d x

\frac{1}{s ^{2} + 16}

What is the tangent of 3x^2+2x,\at x=-1 ?
The tangent of 3x^2+2x,\at x=-1 is y=-4x-3