What is (\partial)/(\partial y)(sin(xy^2)) ?

The answer to (\partial)/(\partial y)(sin(xy^2)) is cos(xy^2)*2xy

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(\partial)/(\partial y)(sin(xy^2))

\frac{\partial}{\partial y} (sin (x y^{2}))

cos (x y^{2}) \cdot 2 x y

Solution steps

\frac{\partial}{\partial y} (sin (x y^{2}))

Treat

x

as a constant

Apply the chain rule:

cos (x y^{2}) \frac{\partial}{\partial y} (x y^{2})

= cos (x y^{2}) \frac{\partial}{\partial y} (x y^{2})

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

= cos (x y^{2}) \cdot 2 x y

\int_{- 1}^{1} x^{4} - 2 x^{2} + 1 d x

\int \frac{y}{y ^{2} - 1} d y

sin (cos (tan (x)))

\frac{\partial}{\partial y} (\frac{x}{y + 2 z})

n = 1 \sum \infty (- 0.75)^{n}

What is (\partial)/(\partial y)(sin(xy^2)) ?
The answer to (\partial)/(\partial y)(sin(xy^2)) is cos(xy^2)*2xy