What is area y=2x^2ln(x),y=8ln(x) ?

The answer to area y=2x^2ln(x),y=8ln(x) is 0.94912…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=2x^2ln(x),y=8ln(x)

area

y = 2 x^{2} ln (x), y = 8 ln (x)

0.94912 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} 2 x^{2} ln (x) - 8 ln (x) d x

Solve

\int_{1}^{2} 2 x^{2} ln (x) - 8 ln (x) d x : 0.94912 \dots

The area is:

= 0.94912 \dots

\int \frac{48}{( t + 1 ) ^{4}} - 3 d t

\frac{d y}{d x} = \frac{x ^{7} - 8 y}{x}

\int_{0}^{1} e^{2 x} d x

2 x y d x - (1 + x^{2}) d y = 0

\int \frac{x ^{2}}{4 - 25 x ^{2}} d x

What is area y=2x^2ln(x),y=8ln(x) ?
The answer to area y=2x^2ln(x),y=8ln(x) is 0.94912…