What is the derivative of 8/(sqrt(x-2)) ?

The derivative of 8/(sqrt(x-2)) is -4/((x-2)^{3/2)}

What is the first derivative of 8/(sqrt(x-2)) ?

The first derivative of 8/(sqrt(x-2)) is -4/((x-2)^{3/2)}

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\frac{d}{d x} (\frac{8}{x - 2})

- \frac{4}{( x - 2 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{8}{x - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} ((x - 2)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 2)

= - \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 8 (- \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

8 (- \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{4}{( x - 2 ) ^{\frac{3}{2}}}

= - \frac{4}{( x - 2 ) ^{\frac{3}{2}}}

\int x^{2} \cdot e^{x^{3} + 4} d x

\frac{d}{d x} (r (θ, x) cos (θ))

y = 4 arcsin (5) x^{5}

(1 + x)^{- 1}

y = - 3 x^{3} - 2 x^{2} - x + 3, (- 1, 5)

What is the derivative of 8/(sqrt(x-2)) ?
The derivative of 8/(sqrt(x-2)) is -4/((x-2)^{3/2)}
What is the first derivative of 8/(sqrt(x-2)) ?
The first derivative of 8/(sqrt(x-2)) is -4/((x-2)^{3/2)}