What is the limit as x approaches 0+of x^{-5} ?

The limit as x approaches 0+of x^{-5} is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of x^{-5}

x \to 0 + lim (x^{- 5})

\infty

Solution steps

x \to 0 + lim (x^{- 5})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= x \to 0 + lim (\frac{1}{x ^{5}})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x^{5} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{\partial}{\partial x} (8 x)

\int 4 π x^{2} d x

y = 8 x e^{x}, (0, 0)

f (x) = \frac{x ^{2} - 2 e ^{x}}{x + 3 e ^{x}}

\int \frac{1}{3} sec^{2} (8 x) d x

What is the limit as x approaches 0+of x^{-5} ?
The limit as x approaches 0+of x^{-5} is infinity