What is the solution for y^{'''}-9y^{''}+y^'-9y=0 ?

The solution for y^{'''}-9y^{''}+y^'-9y=0 is y=c_{1}e^{9t}+c_{2}cos(t)+c_{3}sin(t)

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y^{'''}-9y^{''}+y^'-9y=0

y^{^{'''}} - 9 y^{^{''}} + y^{^{'}} - 9 y = 0

y = c_{1} e^{9 t} + c_{2} cos (t) + c_{3} sin (t)

Solution steps

y^{'''} (t) - 9 y^{''} (t) + y^{'} (t) - 9 y = 0

Solve linear ODE:

y = c_{1} e^{9 t} + c_{2} cos (t) + c_{3} sin (t)

y = c_{1} e^{9 t} + c_{2} cos (t) + c_{3} sin (t)

y^{^{''}} - 4 y^{^{'}} + 3 y = (2 x + 1) e^{- x}

x \to 0 - lim (\frac{0}{x ^{2} ∣ x ∣})

\frac{d}{d x} (\frac{e ^{x}}{3})

\int_{4 y^{2} + 4 z^{2}}^{4} x d x

\frac{d}{d x} ((x^{2} - 1) (x^{3} + 3 x))

What is the solution for y^{'''}-9y^{''}+y^'-9y=0 ?
The solution for y^{'''}-9y^{''}+y^'-9y=0 is y=c_{1}e^{9t}+c_{2}cos(t)+c_{3}sin(t)