What is the sum from i=1 to infinity of (i)*1/(6^i) ?

The sum from i=1 to infinity of (i)*1/(6^i) is converges

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sum from i=1 to infinity of (i)*1/(6^i)

i = 1 \sum \infty (i) \cdot \frac{1}{6 ^{i}}

converges

Solution steps

i = 1 \sum \infty i \frac{1}{6 ^{i}}

Apply Series Ratio Test:

converges

= converges

x \to 2 lim (\frac{x + 2}{x})

\frac{\partial}{\partial y} (x y d x)

\int 3 + x d x

\frac{d}{d x} ((9 x^{6} + 8 x^{3})^{4})

x \to + 1 + lim (x)

What is the sum from i=1 to infinity of (i)*1/(6^i) ?
The sum from i=1 to infinity of (i)*1/(6^i) is converges